For exampUM FX3U K1X0 FX3U K1M0 directive, why is the count the number of X0/X1/X2/X3 four switch ON, SUM K2X0 X0/X1/X2/X3/X4/X5/X6/X7 K1M0 statistics? How to calculate?
Re: Time:2016-2-23 17:13:00
K1X0 X0 4 FX3U that FX3U is, X0~X3,K2X0 is X0 8-bit, that is X0~X7.